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How to find the point slope form with the slope of 3 and the point of -2/6

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:y-6 = 3(x + 2) [/tex]

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[tex] \large \tt Solution \: : [/tex]

Equation of line in point - slope form :

[tex]\qquad \tt \rightarrow \:y-y_1 = m(x - x_1)[/tex]

  • [tex] \tt \:m = slope=3[/tex]

  • [tex]\tt y_1 = y \: \: coordinate \: \: of \: \: point = 6[/tex]

  • [tex] \tt \:x_1 = x \: \: coordinate \: \: of \: \: point = - 2[/tex]

Here :

[tex]\qquad \tt \rightarrow \:y - 6 = 3(x - ( - 2))[/tex]

[tex]\qquad \tt \rightarrow \:y - 6 = 3(x + 2)[/tex]

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