Answer:
12
Step-by-step explanation:
Assuming that the 2 actually represents square, the equation is
[tex]f(x) = 12(x-2)^2 + 18[/tex]
[tex](x-2)^2 = x^2 - 4x + 4\\\\12(x-2)^2 + 18 = 12( x^2 - 4x + 4) + 18 = 12x^2 -48x + 48 + 18 = 12x^2 -48x + 66\\[/tex]
This equation is of the form
[tex]ax^2 + bx + c[/tex]
[tex]a = 12, b = -48, c = 66[/tex]
Note
Since the question is only asking for the a value which is the coefficient of x² it is clear that 12 is the coefficient without expanding (x-2)² but it is always better to proceed as above in case you are asked for b and c values also
Value of the function at x=a is [tex]12a^{2} -240a +1218[/tex].
Given function f(x)=[tex]12(x-10)^{2} +18[/tex]
We have to find the value of function at x=a.
For this we have to just put x=a in the function f(x)=[tex]12(x-10)^{2}+18[/tex]
f(a)=12[tex](a-10)^{2} +18[/tex]
we have to expand (x-10) to the power 2 to get the value of function.
f(a)=[tex]12(a^{2} +10^{2} -20a)+18[/tex]
=[tex]12a^{2}+1200-240a+18\\[/tex]
=[tex]12a^{2} -240a+1218[/tex]
Hence the value of function at x=a is [tex]12a^{2} -240a+1218[/tex] means f(a)=[tex]12a^{2} -240a+1218[/tex].
Learn more about functions at https://brainly.com/question/10439235
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