Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

You are ask to bring a cylindrical rod of length 45cm and diameter of 4.53cm to a mechanic. what is the weight of the aluminum rod if the density is 3.7*10^3kg/m^3

Sagot :

tushargupta0691

26.676 × 10³ kg is the weight of the aluminum rod.

To calculate specific weight:

Given:

Length of cylindrical rod (h) = 45 cm

Diameter of a cylindrical rod = 4.53 cm

Radius of a cylindrical rod (r) = 2.3 cm

The density = 3.7*10^3kg/m^3

Volume of a cylindrical rod = πr²h

                                             = 3.14× (2.3)² × 45

                                             = 747.89 cm

                                             = 7.4789 m

To find weight ;

                         ρ = [tex]\frac{Mass}{Volume}[/tex]                  ; ρ = Density

                        Mass = ρ × Volume

                                  = 3.7 × 7.48 × 10³

                                  =27.676 × 10³ kg

Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.

Learn more about specific weight here:

https://brainly.com/question/13178675

#SPJ4

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.