At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The answer to the first part of the question is 24 V and the answer to the second part of the question is 48 V.
The formula which relates Charge, Capacitance and Voltage is
Charge = Capacitance × Voltage
Q = CV
where Q denotes the charge, C denotes the capacitance and V denote the voltage.
Using the above formula the charge on the capacitance will be
Q = CV
C = 10 mF
V = 24 V
Q = 240 mC
Charge on capacitance is 240 mC.
Now after we disconnect the battery
C = 10 mF (will remain same)
Q = 240 mC
V = Q/C
V = 240/10 V
V = 24 V
So after we removed the battery, The voltage will remain same.
Now we know that parallel plate capacitor formula is
C = ε(A/d)
from here
C ∝ 1/d, and as there is no loss of charge we can say that V ∝ 1/d
Form C ∝ 1/d and V ∝ 1/C we can state that
V ∝ d {where d is the measurement of separation between the plates}
so if we double the distance between the plates then, the voltage will also get double.
Previously our voltage was 24 V, now if we double the distance between the plates the voltage will also get double, and it will become 48 V.
So, the voltmeter will take a reading of 24 V if voltmeter is connected across the two plates without discharging them, and if we double the plate separation then it will take 48 V as reading.
Learn more about Capacitors here:
https://brainly.com/question/13578522
#SPJ10
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
