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10.00 g of LiCl is dissolved in water to make 1.00 L of "Solution A". Then, 100 mL
of solution A were diluted to a volume of 500 mL of "Solution B". What is the
molarity of solution B? (Report your answer to four places past the decimal point.
Moodle is looking for a number only, no units.)

Sagot :

0.47 M is the molarity of solution B if 10.00 g of LiCl is dissolved in water to make 1.00 L of "Solution A".

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

[tex]Molality = \frac{Moles \;solute}{Solvent \;in \;kg}[/tex]

Moles of  LiCl

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{10.00 g}{42.394 g/mol}[/tex]

Moles = 0.2358824362

[tex]Molality = \frac{0.2358824362}{0.5 L}[/tex]

Molarity = 0.4717648724 M =0.47 M

Hence, 0.47 M is the molarity of solution B.

Learn more about moles here:

https://brainly.com/question/8455949

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