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)The width of a rectangle is shown below:

A coordinate plane with a point A at negative 3, 3 and C at negative 3, negative 2.

If the area of the rectangle to be drawn is 20 square units, where should points B and D be located if they lie to the right of points A and C?

B(1, 3) and D(1, −2)
B(3, 3) and D(3, −2)
B(2, 3) and D(2, −2)
B(1, 2) and D(1, −3)

Sagot :

Answer: B(1, 3) and D(1, −2)

Step-by-step explanation:

The distance from A to C is 5, meaning we need the length to be 4.

If they lie to the right, we need to add 4 to the x coordinates, so the x coordinates should be 1, and the y coordinates should be 3 and -2.

The locations of B and D are given by (A) B(1,3) and D(1,-2).

The area of rectangle is given by the product of the length and width of that rectangle.

Area = Length*Width

Distance between two points (a,b) and (c,d) is given by,

[tex]d=\sqrt{(c-a)^2+(d-b)^2}[/tex]

Here in the given question it is mentioned that AC forms width of a rectangle and A is at (-3,3) and C is at (-3,-2)

Now the width is [tex]=\sqrt{(-3-(-3))^2+(-2-3)^2}=\sqrt{0^2+(-5)^2}=\sqrt{25}=5[/tex] unit.

Also it is given that, the area of the rectangle is 20 square units.

So the length is = 20/5 = 4 units

B and D lie to the right of points A and C respectively.

We have to go 4 units right to the A to find B and 4 units right to C to find D.

A is at (-3,3)

then B is at (-3+4,3) = (1,3)

C is at (-3,-2)

So D is at (-3+4,-2) = (1,-2)

Hence correct option is (A) B(1,3) and D(1,-2)

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