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what mass of aluminium is required to produce 500g of aluminium chloride?

2Al + 3Cl₂ --> 2AlCl₃

Sagot :

Answer:

101.18 grams

Explanation:

From the equation you can see that the same number of MOLES will be required as MOLES of aluminum chloride produced.

Mole weight of aluminum chloride = 26.981 + 3 * 35.45 = 133.331 gm

     500 gms of this is then    500 / 133.331 = 3.75 moles

So you need 3.75 moles of aluminum

    3.75 moles * 26.981 g/mole = 101.18 grams of Al

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Answer:

101.18 grams past questions

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