Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

what mass of aluminium is required to produce 500g of aluminium chloride?

2Al + 3Cl₂ --> 2AlCl₃

Sagot :

Answer:

101.18 grams

Explanation:

From the equation you can see that the same number of MOLES will be required as MOLES of aluminum chloride produced.

Mole weight of aluminum chloride = 26.981 + 3 * 35.45 = 133.331 gm

     500 gms of this is then    500 / 133.331 = 3.75 moles

So you need 3.75 moles of aluminum

    3.75 moles * 26.981 g/mole = 101.18 grams of Al

sprayzsprayz6

Answer:

101.18 grams past questions

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.