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Sagot :
None of the equations are parallel or perpendicular to the line jk.
How to know equations that are parallel and perpendicular?
The equation of a line can be interpreted as follows:
y = mx + b
where
- m = slope
- b = y-intercept
Therefore,
Parallel lines have the same slope(m).
Perpendicular line follows the principle below:
- m₁ m₂ = -1
Therefore, let's find equation of jk
(-5, 5)(1, -5)
m = -5 - 5 / 1 + 5 = -10 / 6 = - 5 / 3
using (1, -5)
-5 = - 5 / 3 (1) + b
b = -5 + 5 / 3 = -15 + 5 / 3 = -10 / 3
Therefore,
y = -5 / 3 x - 10 / 3
m = - 5 / 3
6x + 10y = 11
10y = -6x + 11
y = - 6 / 10 x + 11 / 10
y = - 3 / 5 x + 11 / 10
hence, m = - 3 / 5
5x - 3y = 8
3y = 5x - 8
y = 5 / 3 x - 8/3
m = 5 / 3
The equation
learn more equation here: https://brainly.com/question/14379343
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