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CON PROCESOS POR FAVOR

CON PROCESOS POR FAVOR class=

Sagot :

Answer:

[tex] \dfrac{149}{40} [/tex]

[tex] \dfrac{38}{15} [/tex]

Step-by-step explanation:

[tex] (\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =  [/tex]

[tex] = (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10}) [/tex]

[tex] = (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20}) [/tex]

[tex] = \dfrac{67}{40} - (-\dfrac{41}{20}) [/tex]

[tex] = \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2} [/tex]

[tex] = \dfrac{67}{40} + \dfrac{82}{40} [/tex]

[tex] = \dfrac{149}{40} [/tex]

[tex] (-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) = [/tex]

[tex] = (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5}) [/tex]

[tex] = 0 + \dfrac{18}{15} + \dfrac{20}{15} [/tex]

[tex] = \dfrac{38}{15} [/tex]