pilotguy321
Answered

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If the center of a circle is at (5,-7)
and its radius is 6, complete its
equation:

If The Center Of A Circle Is At 57 And Its Radius Is 6 Complete Its Equation class=

Sagot :

manasvivasannagari

The equation is:

(x-5)^2+(y-(-7))^2=36

I hope it helps!

Answer:  [tex]\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}[/tex]

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Work Shown:

[tex](h,k) = (5,-7) = \text{center}\\\\r = 6 = \text{radius}\\\\(x - h)^2 + (y - k)^2 = r^2\\\\(x - 5)^2 + (y - (-7))^2 = 6^2\\\\\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}\\\\[/tex]

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