Answer:
x = 1 or x = -1
Step-by-step explanation:
Given equation:
[tex]x^{100}-4^x \cdot x^{98}-x^2+4^x=0[/tex]
Factor out -1:
[tex]\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0[/tex]
Divide both sides by -1:
[tex]\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0[/tex]
Rearrange the terms:
[tex]\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0[/tex]
[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:[/tex]
[tex]\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0[/tex]
Factor the first two terms and the last two terms separately:
[tex]\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0[/tex]
Factor out the common term [tex](x^{98}-1)[/tex] :
[tex]\implies (4^x-x^2)(x^{98}-1)=0[/tex]
Zero Product Property: If a ⋅ b = 0 then either a = 0 or b = 0 (or both).
Using the Zero Product Property, set each factor equal to zero and solve for x (if possible):
[tex]\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}[/tex]
Therefore, the solutions to the given equation are: x = 1 or x = -1
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