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Sagot :
Step-by-step explanation:
Funtion-A:
Given:
[tex]y = {x}^{2} - x - 6[/tex]
To find the x-intercepts set y to 0 and solve for x which is done below:
- ⇒x²-x-6=0
- ⇒(x-3)(x+2)=0
- X=3 and -2
Therefore x-intercepts:(3,0),(-2,0)
To figure out the y-intercept , substitute 0 for x and simplify
- ⇒y=0²-0-6
- ⇒y=-6
Hence, The y-intercept is (0,-6)
- The vertex (0.5,-6.25)
(skipped the steps as you've already figured it out)
Function-B:
Likewise A:
X-intercepts:
- ⇒-x²+x+6=0
- ⇒x²-x-6=0
- ⇒x=3 and -2
Therefore,x-intercepts:(3,0),(-2,0)
Y-intercept:
⇒y=-0²+0+6
⇒y=6
Therefore, y-intercept (0,6)
The vertex:(0.5,6.25)
Inspection of the Parabolas:
The difference between the two parabolas is that The blue parabola is the result of reflection over x-axis of the red one.
Answer:
a.
The x-intercepts are 3 and -2
The y-intercept is -6
The vertex is (1/2 , -25/4)
b.
The two parabola are symmetric across the x-axis
Step-by-step explanation:
x² - x - 6
[tex]=x^{2}-2\times \frac{x}{2} +\frac{1}{4} -\frac{1}{4}-6[/tex]
[tex]=(x-\frac{1}{2} )^{2} -(\frac{1}{4}+6)[/tex]
[tex]=(x-\frac{1}{2} )^{2} -\frac{25}{4}[/tex]
The x-intercepts :
(x-1/2)² = 25/4
Then
x - 1/2 = 5/2 or x - 1/2 = -5/2
Then
x = 3 or x = -2
The y-intercepts :
We get the y-intercept by replacing x by 0 in the trinomial :
0² - 0 - 6 = -6
b.
we notice that :
-x² + x + 6 = -(x² - x - 6)
Then
-x² + x + 6
[tex]=-(x-\frac{1}{2} )^{2} +\frac{25}{4}[/tex]
The x-intercepts :
[tex]-(x-\frac{1}{2} )^{2} +\frac{25}{4}=0[/tex]
⇔ (x-1/2)² = 25/4
Then
x - 1/2 = 5/2 or x - 1/2 = -5/2
Then
x = 3 or x = -2
The y-intercepts :
We get the y-intercept by replacing x by 0 in the trinomial :
0² + 0 + 6 = 6
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