Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

For the following reaction, 41.0 grams of sulfuric acid are allowed to react with 36.5 grams of zinc hydroxide. What is the maximum amount of zinc sulfate that can be formed? Mass = g What is the FORMULA for the limiting reactant? What amount of the excess reactant remains after the reaction is complete? Mass = g

Sagot :

The FORMULA for the limiting reagent is [tex]ZnOH_2[/tex].

4.27 grams of reactant remains after the reaction is complete.

What is a limiting reagent?

The limiting reagent is the reactant that is completely used up in a reaction and thus determines when the reaction stops.

Given data:

Mass of sulfuric acid = 41.0 grams

Molar mass of sulfuric acid = 98.08 g/mol

Mass of zinc hydroxide = 36.5 grams

Molar mass of zinc hydroxide = 99.424 g/mol

Step 1:moles sulfuric acid = mass sulfuric acid / molar mass sulfuric acid

moles sulfuric acid = 41.0 grams / 98.08 g/mol

moles sulfuric acid = 0.41 moles

Step 2: moles of zinc hydroxide

moles zinc hydroxide = 36.5 grams / 99.424 g/mol

moles zinc hydroxide =0.367 moles

Step 3: Calculate limiting reactant

zinc hydroxide is the limiting reactant. It will completely be consumed.

There will remain 0.41 moles - 0.367 moles = 0.043 moles

This is 0.043 moles x 99.424 g/mol

= 4.27 grams

Learn more about the limiting reagent here:

https://brainly.com/question/14155328

#SPJ1