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A jug of drinking water contained 1 2/3 gallons. If 5/7 gallon is drinked each day, how much water was left in the jug after 2 days?

Sagot :

Answer:

The answer is 5/21 water left in the jug after 2 days.

Step-by-step explanation:

First convert 1 2/3 into a improper fraction. This will turn it into 5/3. After this, find a common denominator between 5/7 and 5/3. This common denominator is 21. Now, convert both fractions into a fraction with 21 as the denominator. This will transform 5/7 into 15/21, and 5/3 into 35/21. So we know from the equation that 15/21 is drank every day. So we multiply 15/21 by 2, which will make it 30/21. 35/21 will stay the same. Now we do 35/21 - 30/21, which gives you the final answer of 5/21 water left in the jug after 2 days.

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