JosephRogersVI
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Find the point Q along the directed line segement from point R (-3, 3) to point S(6, -3) that divides the segment in the ratio 2:1.

A. (3, 0)
B. (6, -4)
C. (0, 1)
D. (3, -1)

Sagot :

brianaperez23

Answer: (3,-1)

Step-by-step explanation:

distance between R & S x values: 9

distance between R & S y values: -6

multiply each by 2/3 (the proportion)

9/1 x 2/3 = 6; -6/1 x 2/3= -4

add the answers to R x & y values:

-3 + 6= 3; 3 - 4= -1

Answer:

D

Step-by-step explanation:

using the section formula

(x₁, y₁ ) and (x₂, y₂ ) divided in the ratio m : n , then

point = ([tex]\frac{mx_{2}+nx_{1} }{m+n}[/tex] , [tex]\frac{my_{2}+ny_{1} }{m+n}[/tex] )

thus for R (- 3, 3 ) and S (6, - 3 ) in the ratio 2 : 1

Q = ( [tex]\frac{2(6)+1(-3)}{2+1}[/tex] , [tex]\frac{2(-3)+1(3)}{2+1}[/tex] )

   = ( [tex]\frac{12-3}{3}[/tex] , [tex]\frac{-6+3}{3}[/tex] )

  = ( [tex]\frac{9}{3}[/tex] , [tex]\frac{-3}{3}[/tex] )

  = (3, - 1 )

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