Answered

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A linear function contains these points: (0,-1) & (3,8)

What is the slope and y-intercept of this function?

Sagot :

fieryanswererft

Answer:

slope: 3

y-intercept: (0, -1)

Find slope:

[tex]\sf slope : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Here given points are: (0, -1), (3, 8)

[tex]\rightarrow \sf slope : \dfrac{8-(-1)}{3-0} = \dfrac{9}{3} = 3[/tex]

When finding y-intercept, the value of x is 0. Here given y is -1 when x is 0.

y-intercept: -1  or  (0, -1)

SOLVING

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

If a linear function contains these points: (0,-1) and (3,8), what is its slope and y-int.?

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

Formula utilised, here [tex]\bf{\dfrac{y2-y1}{x2-x1}}[/tex].

Put in the values,

[tex]\bf{\dfrac{8-(-1)}{3-0}}[/tex]  | subtract on top and bottom

[tex]\bf{\dfrac{9}{3}}[/tex] | divide on top and bottom

[tex]\bf{3}[/tex]

The y-intercept is the second co-ordinate of the point (0,-1)

[tex]\bf{Which\;is\;-1}[/tex].

[tex]\cline{1-2}[/tex]

[tex]\bf{Result:}[/tex]

                      [tex]\bf{\begin{cases} \bf{Slope=3} \\ \bf{Y-int. -1} \end{cases}[/tex]

[tex]\LARGE\boxed{\bf{aesthetic\not1 \theta l}}[/tex]

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