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Sagot :
Substituting in y=15,
[tex]\frac{1}{5}x-\frac{2}[3}(15)=30\\\\\frac{1}{5}x-10=30\\\\\frac{1}{5}x=40\\\\x=\boxed{200}[/tex]
Answer: x = 200
Step-by-Step Solution:
=> 1/5x - 2/3y = 30 ; when y = 15
Substitute the value of ‘y’ :-
1/5x - 2/3y = 30
x/5 - 2(15)/3 = 30
x/5 - 30/3 = 30
x/5 - 10 = 30
x/5 - 50/5 = 30
x - 50 = 30 * 5
x - 50 = 150
x = 150 + 50
=> x = 200
Therefore, x = 200
Step-by-Step Solution:
=> 1/5x - 2/3y = 30 ; when y = 15
Substitute the value of ‘y’ :-
1/5x - 2/3y = 30
x/5 - 2(15)/3 = 30
x/5 - 30/3 = 30
x/5 - 10 = 30
x/5 - 50/5 = 30
x - 50 = 30 * 5
x - 50 = 150
x = 150 + 50
=> x = 200
Therefore, x = 200
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