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Sagot :
Answer:
7.21
Step-by-step explanation:
There is a formula to find the area of a side of a rhombus given 2 diagonals.
It is: [tex]\frac{\sqrt{p^{2}+q^{2} } }{2}[/tex]
64 + 144 = 208
[tex]\sqrt{208}[/tex] = 14.42
14.42 / 2 =
7.21
The diagonals of the rhombus meet perpendicularly, so you have four right triangles. Because of this you can use the Pythagorean theorem with 8 and 12 to find the side.
Theorem: a^2 + b^2 = c^2
8^2 + 12^2 = c^2
64+144 = c^2
c^2 = 208
c = sqrt208
Theorem: a^2 + b^2 = c^2
8^2 + 12^2 = c^2
64+144 = c^2
c^2 = 208
c = sqrt208
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