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your favorite basketball player has an 90% free-throw percentage. In the next game that s/he plays they shoot 12 free throws. What is the probability that they make all 12

Sagot :

The probability that favourite basketball player make all 12 is 0.

Give 90% free- throw percentage of favourite basketball player and he has taken 12 shots in the game.

Probability is the chance of happening an event among all the events possible. It lies between 0 and 1.

This is a binomial probability question "makes" is what some writer call a "success". In the binomial probability distribution, the probability of r successes in trials is :

=[tex]nC^{r}[/tex][tex]p_{r}p^{r}(1-p)^{n-r}[/tex]

p is the probability of "success" n p r=n!/((n-r)!

n [tex]p_{n}[/tex]=0

In this problem , n=12, r=12,p=0.9. the probability of exactly 12 made shots out of 12 attempted is 12[tex]C_{12} (0.90)^{12} (1-0.90)^{0}[/tex].

=12!/12!(12-12)!*[tex](0.90)^{12}(0.10)^{0}[/tex]

=0

Hence the probability that they make all 12 is 0.

Learn more about probability at https://brainly.com/question/24756209

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