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You attend a wedding and are second in line to get a slice of wedding cake. there are 3 slices of vanilla cake, 12 slices of chocolate cake, and 6 slices of red velvet cake left. they are being handed out by a waiter at random. what is the probability that both you and the person in line in front of you get red velvet cake?

Sagot :

rvkacademic

Answer:

1/14

Step-by-step explanation:

Let A represent the event First person getting red velvet cake
Let B represent the event Second person getting red velvet cake

P(A) = Total number of Red Velvet Cakes ÷ Total Number of Cakes =

6/21 = 2/7

If the first person gets a red velvet cake, then there are 5 red velvet cakes and 20 total cakes

Therefore P(B|A) = Number of red velvet cakes left ÷ total number of cakes left = 5/20 = 1/4

P(A and B) == probability of both getting red velvet cake P(A∩B) = P(A).P(B|A) = 2/7 × 1/4 = 2/28 = 1/14

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