Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

How many moles of electrons are transferred when 2.0 moles of aluminum metal react with excess copper(II) nitrate in aqueous solution to form Al(NO3)3(aq) and Cu(s)

Sagot :

Moles of electrons:

The moles of electrons that are transferred are 12F

A balanced equation:

2 moles of Aluminium metal react with excess copper(II) nitrate.

[tex]2Al + 3Cu{(NO_3)}_2 \rightarrow 2Al{(NO_3)}_3 +3 Cu[/tex]

Given:

Moles of Aluminium = 2

As Aluminium goes from 0 to +3 oxidation state

[tex]Al \rightarrow Al^{3+} + 3e^-[/tex]

And copper goes from +2 to 0

[tex]Cu^{2+} + 2e^-\rightarrow Cu[/tex]

On balancing the number of electrons we get:

For 1 mole of Al [tex]6e^-[/tex] is required.

Therefore for 2 moles of Al,

Total [tex](2\times6)[/tex]F mole of electrons

Where F= Faraday's constant= 96500 C

So, 12F moles of electrons are transferred.

Learn more about Faraday's Law here,

https://brainly.com/question/27985929

#SPJ4

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.