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A coffee shop owner wants to examine the number of customers who pass in front of his store in the morning from 7:00am to 7:30am. Suppose that the mean number of customers during this time window is 200. What is the probability that more than 210 people will pass in front of his store

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anuksha0456

The probability that more than 210 people will pass in front of his store is 0.2272.

In the question, we are given that a coffee shop owner wants to examine the number of customers who pass in front of his store in the morning from 7:00 A.M to 7:30 A.M.

We are asked to find the probability that more than 210 people will pass in front of his store if the mean number of customers during this time is 210.

This experiment follows a Poisson Distribution with a mean (λ) = 200, and the random variable X = 210.

To find the probability that more than 210 people will pass in front of his store, we will find P(X > 200).

P(X > 200) = 1 - P(X ≤ 210).

Now, P(X ≤ 210) can be calculated using the function poissoncdf(200,210) on the calculator.

As to find the probability of a Poisson Distribution P(X ≤ x), for a mean = λ, we use the calculator function poissoncdf(λ,x).

The value of poissoncdf(200,210) = 0.77271.

Thus, the value of P(X > 210) = 1 - 0.77271 = 0.22729.

Thus, the probability that more than 210 people will pass in front of his store is 0.2272.

Learn more about Poisson Distribution at

https://brainly.com/question/7879375

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