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On October 23, 2011, one U.S. dollar was worth 13.65 Mexican pesos.
(a) On that date, how many pesos was 81.35 dollars worth?
Round your answer to the nearest hundredth of a peso.
0 pesos
(b) On that date, how many dollars was 91.03 pesos worth?
Round your answer to the nearest hundredth of a dollars. I need help with both of these math problems.

Sagot :

Taking into account the rule of three, 1110,4275 Mexican pesos was 81.35 dollars worth and 6.67 dollars was 91.03 Mexican pesos worth.

Rule of three

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following expression must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: [tex]x=\frac{cxb}{a}[/tex]

Amount of Mexican pesos in this cases

On October 23, 2011, one U.S. dollar was worth 13.65 Mexican pesos. So, you can apply the following rules of three:

  • If 1 dollar is equal to 13.65 Mexican pesos, 81.35 dollars is equal to how many Mexican pesos?

1 dollar ⇒ 13.65 Mexican pesos

81.35 dollars ⇒ x

So: [tex]x=\frac{81.35 dollarsx13.65 Mexican pesos}{1 dollar}[/tex]

Solving:

x= 1110,4275 Mexican pesos

  • f 13.65 Mexican pesos is equal to 1 dollar, 91.03 Mexican pesos is equal to how many dollars?

13.65 Mexican pesos ⇒ 1 dollar

91.03 Mexican pesos ⇒ x

So: [tex]x=\frac{91.03 Mexican pesosx 1 dollar}{13.65 Mexican pesos}[/tex]

Solving:

x= 6.67 dollars

In summary, 1110,4275 Mexican pesos was 81.35 dollars worth and 6.67 dollars was 91.03 Mexican pesos worth.

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