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Sagot :
The solubility (in M) of O2 in the blood of a scuba diver at a depth of 100 feet is 2.32 × 10^-3 mol.
How to calculate the solubility?
It should be noted that the partial pressure of oxygen will be:
= Mole fraction × Total pressure
= 0.209 × 3
= 0.627
According to Henry's law, the solubility will be:
= 3.7 × 10^-2 × 0.627
= 2.32 × 10^-3 mol
Learn more about blood on:
brainly.com/question/920424
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