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Sagot :
Answer:
The total energy that an electron and positron share is 5 Mev
Explanation:
One of the potential ways that gamma rays interact with matter is by the formation of positron-electron pairs.
The pair production requires a minimum gamma-energy of 1.02 MeV since an electron's rest mass is equal to 0.511 MeV of energy. The electron-positron pair receives any extra kinetic energy from the pair-producing gamma ray.
The reaction is represented by γ =(. - 1e⁰) + (. + 1e⁰)
E = m₀C² + [tex]KE_{electron}[/tex] + m₀C² + [tex]KE_{positron}[/tex]
10 MeV = 2m₀C² + [tex]KE_{electron}[/tex] + [tex]KE_{positron}[/tex]
[ 2m₀C²= 1.02 ] and since the mass of electron and positron is the same, the Kinetic energy (KE), 1/2 mv² will also be the same
Therefore,
KE = 1/2(10 - 1.02)
=4.49 MeV
[ 2m₀C²= 1.02 so, m₀C² = 1.02/ 2 = 0.51]
Total energy shared = m₀C² + KE
= 0.51 + 4.49
= 5 Mev
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