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Sagot :
Answer:
The resistance of the each bulb is 1.75 ohm.
Explanation:
The Power P supplied by the battery is given by the formula,
P=VI
where V is the voltage and I is the current.
Then the total current through given parallel circuit is I=P/V
Given P=48 W and V=6 V the value of I is
I=48 W/6 V
I= 8 A
Since both bulbs have same resistance and are connected in parallel so the current through each circuit will be half of the total current. Hence the current through each circuit I₀ is 4 A.
The Resistance R is calculated using formula R=V/I₀.
So the resistance is
R=6 V/4 A
R=1.75 ohm
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Answer:
The resistance of the bulb is 1.5 ohm.
Explanation:
The power P delivered to the whole circuit is given by the formula,
P=VI
Given P= 48 W and V= 6V, the current in the circuit is
I=P/V
I=48/6= 8 A.
Since the bulbs are identical and are in parallel, therefore the current through each parallel circuit is half of the total current. Therefore current I1 through each bulb is 4 A.
The resistance is given by the formula,
R=V/I1
Hence R=6/4 = 1.5 ohm
Checkout similar question
brainly.com/question/15301856
#SPJ10
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