At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Work done by the friction force is 110.77 J
Calculation of friction force:
here box has mass, m=5.9 kg
It slides the distance of, d=9.3 m
coefficient of kinetic friction is 0.206
Now we can say that,
net force on the object is applied force and friction force
The net force according to Newton's second law:
F(net)=m*a
F(applied) - f(friction) = m*a
The work done by friction force will be
W= -k*mg*d
here g is gravitational acceleration.
substituting the values we get,
W=-(0.206)*(5.3)(9.8)*(9.3)
W= -110.77 J
negative sign denotes the opposite direction.
work done by the friction force is 110.77 J
Learn more about friction force here:
https://brainly.com/question/11507038
#SPJ4
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.