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Sagot :
200 is the minimum number of televisions Robert must sell if he wants to meet his quota of $100,000 in total sales.
Given, that The price of each computer is $545, there is an 8% discount.
8% of 545, then = [tex]\frac{8}{100} *545[/tex]
= $43.60
The discounted price is = $545 ₋ $43.60
discounted price = $501.40
Let n represent the quantity of sold televisions. To reach the required amount of 100,000, the total sales of n televisions at a price of $501.40 apiece must equal 501.40n. Divide by 501.40 to obtain n.
n ≥[tex]\frac{100000}{501.40}[/tex]
Estimate 501.40 as 500 to get =[tex]\frac{100000}{500}[/tex] = 200
Calculate whether the quota is met by multiplying 200 by $501.40 to arrive at $100,280. Since this exceeds $100,000, the sale of 200 televisions satisfies the quota.
To know more about Sales refer to: https://brainly.com/question/23897280
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