Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The probability that a person will be entertained by either books or TV is 0.55
What is the required probability?
Express the given percentages as probabilities.
Let the probability of people being entertained by books be represented as
P(A)=0.36
Probability of people entertained by watching TV,
P(B)=0.32
Probability of people entertained by both books and TV,
P(A∩B)=0.13
P(A) + P(B) - P(A and B) is the formula for calculating the either/or probability for overlapping events. This formula is identical to the non-overlapping events, but we need to take the likelihood that the outcomes could occur simultaneously into account.
Thus, the probability of people being entertained by either books or TV is,
P(AUB)=P(A)+P(B)-P(A∩B)
=0.36+0.32-0.13
=0.68-0.13
=0.55
Learn more about probability here:
https://brainly.com/question/24756209
#SPJ4
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
