At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
The decrease in energy for a lightning flash, with a potential difference between a cloud and the ground, is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C is [tex]$3.555 \times 10^{10} \text{ J}$[/tex].
Explanation:
In a lightning flash, the potential difference between a cloud and the ground is [tex]1.5 \times 10^{9}\text{ V}[/tex] and the quantity of charge transferred is 23.7 C.
It is required to determine the decrease in energy of the transferred charge.
It is known that the decrease in energy is calculated by multiplying the potential difference by the quantity of charge. Mathematically it is expressed as:
[tex]\Delta U=q \Delta V[/tex]
In this problem, the value of q is 23.7 C and the value of [tex]\Delta V[/tex] is [tex]1.5 \times 10^{9}\text{ V}[/tex].
Therefore the decrease in energy is:
[tex]$\begin{aligned}\Delta U&=q \Delta V\\&=23.7\times 1.5 \times 10^{9} \text{ J}\\&=3.555\times 10^{10} \text{ J}\end{aligned}$[/tex]
To know more about the decrease in energy of a transferred charge, refer to:
https://brainly.com/question/14838517
#SPJ4
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
