So Explicit formula for 2nd one
Or general formula as per Geometric progression
For 50 years there are 365(50)=18250days excluding leap years (We will check for leap year if neck to neck situation arises)
Now find sum
Sum of 18250 terms
[tex]\\ \rm\Rrightarrow \dfrac{a(r^n-1)}{r-1}[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{1(2^{18250}-1)}{2-1}[/tex]
1 from both denominator and numerator cancels out
[tex]\\ \rm\Rrightarrow 2^{18250}-1[/tex]
[tex]\\ \rm\Rrightarrow 6.272214002E5493[/tex](Accurate)
It's far more than 1 M so second option would give you more penny
