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Consider being at the top of cliff and throwing a book off the ledge. The book leaves at an angle of 52 degrees and a velocity of 16.0 m/s. If it moves through the air for 13.4 seconds, how far does it fall

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onyebuchinnaji

The vertical distance through which the book falls is determined as 1,048.8 m.

Height of the book fall

The vertical distance through which the book falls is calculated as follows;

h = vt + ¹/₂gt²

where;

  • h is height of fall
  • v is initial vertical velocity
  • g is acceleration due to gravity

h = (16 x sin52)(13.4)  + (0.5)(9.8)(13.4²)

h = 1,048.8 m

Thus, the vertical distance through which the book falls is determined as 1,048.8 m.

Learn more about height of fall here:  https://brainly.com/question/15611384

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