Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Consider being at the top of cliff and throwing a book off the ledge. The book leaves at an angle of 52 degrees and a velocity of 16.0 m/s. If it moves through the air for 13.4 seconds, how far does it fall

Sagot :

The vertical distance through which the book falls is determined as 1,048.8 m.

Height of the book fall

The vertical distance through which the book falls is calculated as follows;

h = vt + ¹/₂gt²

where;

  • h is height of fall
  • v is initial vertical velocity
  • g is acceleration due to gravity

h = (16 x sin52)(13.4)  + (0.5)(9.8)(13.4²)

h = 1,048.8 m

Thus, the vertical distance through which the book falls is determined as 1,048.8 m.

Learn more about height of fall here:  https://brainly.com/question/15611384

#SPJ1

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.