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Maya, lute and aran are cousins. maya's age is 1/3 of lute's and aran is 1/4 of lute's age. if the sum of their agaes is 38, find the ages of each cousin

Sagot :

The ages of Lute,  Maya and Aran are respectively; 24, 8 and 6 years old.

How to solve algebra problems?

Let Lute's age be x

Thus;

Maya's age = ¹/₃x

Aran's age = ¹/₄x

We are told the sum of their ages is 38. Thus;

x + ¹/₃x + ¹/₄x = 38

Multiply through by 12 to get;

12x + 4x + 3x = 456

19x = 456

x = 456/19

x = 24

Maya's age =  ¹/₃ * 24 = 8 years

Aran's age = ¹/₄ * 24 = 6 years

Read more about Algebra Problems at; https://brainly.com/question/723406

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