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A mass of 26.1 g of an element is known to contain 6.87 x 1023 atoms. What is the atomic mass of the element

Sagot :

Medunno13

Using Avogadro's law, we know the amount of moles in the sample is

[tex]\frac{6.87 \times 10^{23}}{6.022 \times 10^{23}}=1.1408170043175 \text{ mol}[/tex]

Therefore, the atomic mass is:

[tex]\frac{26.1}{1.1408170043175}=\boxed{22.9 \text{ g/mol (to 3 sf)}}[/tex]

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