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Sagot :
Her acceleration on the rough patch is 2.8m/s².
To find the answer, we need to know about the Newton's equation of motion.
What are the Newton's equation of motion?
These are as follows
- V= U +at
- S = Ut+1/2 at²
- V²-U²= 2aS
V= Final velocity
U = initial velocity
t= time
S= distance
What will be acceleration if initial velocity, final velocity and distance are 8 m/s , 6 m/s and 5m respectively?
- Here U= 8 m/s, V = 6 m/s and S = 5m
- So, 6²-8²= 2a× 5=10a
36-64 = 10a
-28= 10 a
a= -28/10= -2.8 m/s²
- Negative sign indicates the decrease of acceleration.
Thus, we can conclude that the acceleration on the patch is 2.8 m/s².
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
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