Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Her acceleration on the rough patch is 2.8m/s².
To find the answer, we need to know about the Newton's equation of motion.
What are the Newton's equation of motion?
These are as follows
- V= U +at
- S = Ut+1/2 at²
- V²-U²= 2aS
V= Final velocity
U = initial velocity
t= time
S= distance
What will be acceleration if initial velocity, final velocity and distance are 8 m/s , 6 m/s and 5m respectively?
- Here U= 8 m/s, V = 6 m/s and S = 5m
- So, 6²-8²= 2a× 5=10a
36-64 = 10a
-28= 10 a
a= -28/10= -2.8 m/s²
- Negative sign indicates the decrease of acceleration.
Thus, we can conclude that the acceleration on the patch is 2.8 m/s².
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
#SPJ4
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.
