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Answered

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5) Solve the simultaneous equations log(x+y)=0 Solve the simultaneous equations 2logx=log(y+1)​

Sagot :

Answer:

(1,0)

Step-by-step explanation:

Since log (x+y) = 0        you should know  x+y = 1

                                            so y = (1-x)

then   2 logx = log (y+1)

          log x^2 = log (1-x   +1) = log (2-x)

                x^2 = 2-x

                 x^2 + x-2 = 0

                 (x+2)(x-1) = 0      so x = -2  or   +1

                                               then y = 3  or 0

-2,3    and   1,0       since you cannot have a log of a negative number

                                     the only answer is (1,0)  

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