The ionized uranium (238 [tex]U^{5+}[/tex]) has 92 protons, 146 neutrons and 87 electrons.
The U²³⁸ is a stable isotope of Uranium. It cannot sustain a chain reaction.
The atomic number for uranium is 92 and its atomic mass is 238.
The atomic number for U²³⁸ is 92.
So, the number of protons or electrons = 92
Then, the number of neutrons = atomic mass - number of protons
⇒ 238 - 92 = 146
The Uranium is ionized and becomes ²³⁸U⁵⁺.
So,
The number of protons = 92
The number of electrons = 92 - 5 = 87 (Since uranium is ionized by 5+ electrons i.e., removing 5 electrons)
The number of neutrons = atomic mass - number of protons
= 238 - 92 = 146
Thus, when uranium ionizes and becomes ²³⁸U⁵⁺, there are 92 protons, 146 neutrons, and 87 electrons.
Learn more about isotopes of Uranium here:
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