Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The unit digit of a two digit number is one less than the ten digit number. If the number is increase by 8 and then divided by the unit of the digits, the results is 8. Find the number.

Sagot :

The tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

Lets simplify the problem,

Let assume  the "tens" digit be x

Then the "units" difference =  (x-1), according to the condition.

Hence, the number itself is N = 10x + (x-1).

Then the number N+8 is 10x + (x-1) + 8 = 10x + x + 7 = 11x + 7.

From the last statement of the problem, we have this equation

[tex]N+8 = 8*(x+y),or11x + 7 = 8*(x+(x-1)).[/tex]

Simplify and find "x"

[tex]11x + 7 = 8*(2x-1)11x + 7 = 16x - 87 + 8 = 16x - 11x15 = 5xx = 15/5 = 3[/tex].

Thus the tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

Learn more about UNIT Problems on:

https://brainly.com/question/12253743

#SPJ4