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The quadratic $x^2 1300x 1300$ can be written in the form $(x b)^2 c$, where $b$ and $c$ are constants. What is $\frac{c}{b}$

Sagot :

anuksha0456

The value of c/b when the quadratic equation x² + 1300x + 1300 is written in the form (x + b)² + c, b and c being constants is -648.

The given quadratic expression needs to be expressed using the perfect square method to be of the form (x + b)² + c.

We express the quadratic expression x² + 1300x + 1300 using the perfect square method following these steps:

x² + 1300x + 1300

= x² + 2x(1300/2) + (1300/2)² + 1300 - (1300/2)²

= x² + 2x(650) + (650)² + 1300 - (650)²

= (x + 650)² + 1300 - 422500

= (x + 650)² - 421200.

Comparing this to (x + b)² + c, we get:

b = 650, and c = -421200.

Therefore, the value of c/b = (-421200)/650 = -648.

Therefore, the value of c/b when the quadratic equation x² + 1300x + 1300 is written in the form (x + b)² + c, b and c being constants is -648.

The question seems improper. The proper question is:

" The quadratic x^2+1300x+1300 can be written in the form (x + b)^2+c, where b and c are constants. What is c/b?"

Learn more about quadratic equations at

https://brainly.com/question/24929362

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