The concentration of the solution in units of molarity is 0.64 M and the concentration of the solution in terms of g/mL is 0.10976 g/mL.
The measure of the amount of the solute dissolved in the given amount of the solvent or solution is said to be the concentration of the solution.
It is given by the expression,
Concentration of the solution = mass of the solute/total volume of the solution
Units: g/mL
The concentration of the solution in units of molarity is given by the expression,
Molarity = (no. of moles of the solute)/(Volume in L)
Units: moles/L
It is given that the solute is barium hydroxide - Ba(OH)₂
The mass of Ba(OH)₂ = 2.81 g
When in dissolved in water, the total volume of the solution = 25.6 mL
The molar mass of Ba(OH)₂ = 171.34 g/mol
Then,
No. of moles = (mass of Ba(OH)₂)/(molar mass of Ba(OH)₂)
i.e.,
No. of moles = [tex]\frac{2.81}{171.34}[/tex] = 0.0164 mole
Concentration = mass of the solute/total volume
I.e., C = [tex]\frac{2.81}{25.6}[/tex] = 0.10976 g/mL
Then the concentration of the solution in units of molarity is,
Molarity = (no. of moles)/(Volume of the solution in L)
⇒ Molarity = [tex]\frac{0.0164}{25.6/1000}[/tex] = 0.64 M
Therefore, the concentration of the solution in units of molarity is 0.64 M.
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