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Triangle A C B is cut by bisector C D. The lengths of sides A C and C B are congruent.

CD bisects ∠ACB. Which statements must be true? Check all that apply.
AD = BD
AC = CD
m∠ACD = m∠BCD
m∠CDA = m∠CDB
m∠DCA = m∠DAC


Sagot :

The statements that are true are AD = BD  , m∠ACD = m∠BCD , m∠CDA = m∠CDB , Option A , C and D

What is a Triangle ?

A triangle is a polygon with three sides , angles and vertices.

It is given a Δ ACB

CD is the angle bisector of ∠ACB

AC ≅ CB

To determine which statement are true

First it has to be proved that Δ DCB is congruent to Δ ACD

In the triangles

AC = CB (Given )

∠ACD =  ∠DCB (CD is the angle bisector of ∠ACB)

DC = DC ( Common side )

thus Δ DCB is congruent to Δ ACD

Therefore the following statements are true

AD = BD (CPCTC)

m∠ACD = m∠BCD (CPCTC)

m∠CDA = m∠CDB (CPCTC)

Therefore Option A , C and D are the statements that are true .

To know more about Triangle

https://brainly.com/question/2773823

#SPJ1

Answer:

A, C, D

Step-by-step explanation:

Correct on edg

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