Answered

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A balloon contains 10.0 g of helium gas. If the initial volume is V, and the temperature
and pressure are held constant, what is the final volume (in terms of V) after 10.0 g
of neon is added?

Sagot :

Answer:

1.2 V

Explanation:

10 g helium = 2.5 moles He

10 g Neon = ~ .5 mole neon

2.5 is to V as   (2.5 + .5) is to x

2.5 / V = 3/x

2.5 x = 3 V

x = 3/2.5 V = 1 1/5 V

indrawboy

Avogadro's Law (P,T constant)

[tex]\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}[/tex]

n = mol

V = volume

AM He = 4 u, mol = 10 : 4 = 2.5

AM Ne = 20 u, mol = 10 : 20 = 0.5

[tex]\tt \dfrac{V}{2.5}=\dfrac{V_2}{2.5+0.5}\\\\V_2=\boxed{\bold{1.2V}}[/tex]

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