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Sagot :
Here use general math mind
F(x) has more than one x inetercept .
- We shall take one quadratic function in which will give 2 intercepts(Real)
Domain is for real numbers
Four unique numbers?
- Add 4 constants for 4 unique definations and that shouldn't fall under quadratic region
Lets see
[tex]\sf f(x)=\begin{cases}\sf (x+2)²,x\neq \left\{0,-1,1,2,3\right\}\\ \sf 0,x=0\\ \sf 1,x=-1\\ \sf 9,x=1\\ \sf 16,x=4\\ \sf 25,x=5\end{cases}[/tex]
- Has 2 x intercepts
For -2
- y=(0)²=0
- (-2,0)
For 0 it's (0,0)
And for extra ,it's discontinuous on x=0
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