Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A
How to compare the energy released?
The given parameters are:
Energy A = 5.1 * 10^7
Energy B = 1.5 * 10^11
The amount of energy B in proportion to energy A is calculated as
Proportion = Energy B/Energy A
So, we have:
Proportion = (1.5 * 10^11)/(5.1 * 10^7)
Divide 1.5 by 5.1
Proportion = 0.2941 * 10^11/10^7
Divide 10^11 by 10^7
Proportion = 0.2941 * 10^4
Evaluate
Proportion = 2941
Hence, fission of 1 kg of element B releases 2941 times as much energy as burning 1 kg of element A
Read more about quotient at:
https://brainly.com/question/673545
#SPJ1
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.