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How many grams of aluminum phosphate is produced from 7.5 g of lithium phosphate in this balanced equation? 2Li3PO4 + Al2(SO4)3 = 3Li2SO4 + 2AlPO4

Sagot :

7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

[tex]2Li_3PO_4 + Al_2(SO_4)_3[/tex]→ [tex]3Li_2SO_4 + 2AlPO_4[/tex]

Moles of 7.5 g of lithium phosphate.

The molar mass of lithium phosphate is 115.79 g/mol.

Moles = [tex]\frac{mass}{molar \;mass}[/tex]

Moles =[tex]\frac{7.5 g}{115.79 g/mol}[/tex]

Moles = [tex]\frac{7.5 g}{115.79 g/mol}[/tex]

Moles = 0.06477243285

Now we will compare the moles of [tex]AlPO_4[/tex] with [tex]Li_3PO_4[/tex].

               [tex]Li_3PO_4[/tex]               :     [tex]AlPO_4[/tex]

                   2            :               2

                0.385       :              2÷2× 0.064 = 0.064 mol

Mass of [tex]AlPO_4[/tex] :

Mass of [tex]AlPO_4[/tex] = moles × molar mass

Mass of [tex]AlPO_4[/tex] =0.064  mol × 121.9529 g/mol

Mass of [tex]AlPO_4[/tex] =  7.8049856 g

Hence, 7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

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