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You drive 7.50 km in a straight line in a direction 10° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)


km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.

Sagot :

a)The distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.

b)Both the routes have the same distance.

What is displacement?

Displacement is defined as the shortest distance between the two points.

Distance is the horizontal length covered by the body, while displacement is the shortest distance between the two points. Displacement is a vector quantity.

Given data;

Distance,d = 7.5 km

Angle,θ=10° E of N

From the triangle ABD and ABC it is obtained that;

AC = AB sinθ

AC=7.5 sin(10°)

AC=1.302 km

CB = 7.5 cos 10°

CB = 7.386 km

AC is the distance in the east direction = 1.302 km

CB is the distance in the north direction = 7.386 km

Both the routes have the same distance. Hence you still arrive at the same point if the East and North legs are reversed in order.

Hence the distance in the east direction and distance in the north direction will be 1.302 km and 7.386 km respectively.

To learn more about displacement, refer to the link: https://brainly.com/question/10919017.

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