If the salesman chooses highway route 1 he will arrive in the shortest time because the distance in route 1 is less than the distance in route 2.
It is defined as the formula for finding the distance between two points. It has given the shortest path distance between two points.
The distance formula can be given as:
[tex]\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
Route 1:
The distance between A and D
Distance of AB:
[tex]\rm AB=\sqrt{(400-0)^2+(300-0)^2}[/tex]
AB = 500 mi
Distance between BD:
[tex]\rm BD=\sqrt{(1300-400)^2+(1500-300)^2}[/tex]
BD = 1500 mi
In route 1 the distance traveled by salesman:
AD = 500 + 1500 = 2000 mi
Route 2:
[tex]\rm AC=\sqrt{(800-0)^2+(1500-0)^2}[/tex]
AC = 1700 mi
[tex]\rm CD=\sqrt{(1300-800)^2+(1500-1500)^2}[/tex]
CD = 500 mi
AD(through C) = 1700 + 500 = 2200 mi
Thus, if the salesman chooses highway route 1 he will arrive in the shortest time because the distance in route 1 is less than the distance in route 2.
Learn more about the distance formula here:
brainly.com/question/18296211
#SPJ1
