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Sagot :
The angle above the horizontal of the motion of mass A + B after the collision. as well as others are mathematically given as
- [tex]\theta f = 26.3 \deg[/tex]
- vf/vA= 0.94
- 2vf^2 / 5vA^2 = 0.35
What is Collison equilibrium?
According to the collision hypothesis of chemistry, chemical reactions happen when two molecules or atoms collide.
Generally, the equation for Collison equilibrium is mathematically given as
For horizontal motion
mvAx+m2vAx = 2mvfx
For vertical motion
-mvAy+m2vAy = 2mvfy
vfy = 1/2 vAy
[tex]\tan \theta f = vfy/vfx \\\\\tan \theta f = 1/3 vAy/vAx \\\\\tan \theta f = vAy/vAx \\\\\theta f = tan-1 ( 1/3 tan (56) )\\\\[/tex]
[tex]\theta f = 26.3 \deg[/tex]
(b)
[tex]v fy = vf sin \theta f\\\\vAy = vA sin theta i\\\\vf/vA = vfy/vAy sin( \theta i)/sin(\theta f)\\\\vf/vA = 1/2 sin(56)/sin(26.3) \\\\[/tex]
vf/vA= 0.94
(c)
[tex]Ef/Ei = \frac{(1/2 * (2m) * (vf)^2) }{ (1/2 * m * (vA)^2) + 1/2*m*(2vA)^2) ]}[/tex]
2vf^2 / 5vA^2 = 0.35
In conclusion, The angle above the horizontal of the motion of mass A + B after the collision. as well as others
[tex]\theta f = 26.3 \deg[/tex]
vf/vA= 0.94
2vf^2 / 5vA^2 = 0.35
Read more about collision theory
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