Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How many grams of NH3 form when 22g H2 react completely?

Sagot :

The Answer to the question is 124.66 grams approximately.

It is given that H₂ will react completely

Molar mass of H₂ = 2 × 1 = 2 gm/mol

Given mass of H₂ = 22 gm

Moles of H₂ reacting = given mass of H₂ / molar mass of H₂

Moles of H₂ reacting = 22 / 2 moles = 11 moles

So, 11 moles of H₂ are taking part in reaction.

The Balanced chemical reaction is as follows as:

N₂ + 3 H₂ → 2 NH₃

It is clear from the reaction that 3 moles of H₂ are making 2 mole of NH₃

3 moles of H₂ → 2 mole of NH₃

1 moles of H₂ → 2/3 mole of NH₃

11 moles of H₂ → (2/3)×11 mole of NH₃

11 moles of H₂ → 22/3 mole of NH₃

So, 11 moles of H₂ will make 22/3 mole of NH₃

22/3 mole NH₃ = mass formed NH₃ / molar mass of NH₃

mass formed NH₃ = 22/3 × molar mass of NH₃

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 22/3 × 17

mass formed NH₃ = 124.66 grams    (approximately)

124.66 grams of NH₃ will be formed.

So, approximately 124.66 grams of NH₃ is formed from 22 grams of H₂.

Learn more about Stoichometry here:

brainly.com/question/25829169

#SPJ10

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.