Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The Answer to the question is 133.34 grams approximately.
As Al is in excess so, complete HCl will consume in reaction.
Molar Mass of HCl = Atomic mass of H + Atomic mass of Cl
Molar Mass of HCl = 1 + 35.45 = 36.45
Number of moles of HCl which reacting will excess Al are
moles = given mass / molar mass
moles = 108 / 36.45 = 2.96 moles of HCl
So 2.96 moles of HCl are taking part in reaction which is approximately 3 moles
The chemical reaction is as follows as:
3 HCl + (excess) Al → AlCl₃ + 3 H
It is clear from the reaction that 3 moles of HCl are making 1 mole of AlCl₃
So in our reaction also 3 mole of HCl is taking part which mean that it will form 1 mole of AlCl₃ .
1 mole AlCl₃ = mass formed AlCl₃ / molar mass of AlCl₃
mass formed AlCl₃ = molar mass of AlCl₃
mass formed AlCl₃ = 133.34 grams
So, approximately 133.34 grams of AlCl₃ is formed when we react 108 grams of HCl with excess AlCl₃.
Learn more about Stoichometry here:
https://brainly.com/question/25829169
#SPJ10
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
